What is the solution for (dy)/(dx)=y^{1/3} ?

The solution for (dy)/(dx)=y^{1/3} is

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(dy)/(dx)=y^{1/3}

\frac{d y}{d x} = y^{\frac{1}{3}}

y = \frac{2 2 x ^{3} + c _{1}^{3} + 3 c _{1} x ^{2} + 3 c _{1}^{2} x}{3 3}, y = - \frac{2 2 x ^{3} + c _{1}^{3} + 3 c _{1} x ^{2} + 3 c _{1}^{2} x}{3 3}

Solution steps

\frac{d y}{d x} = y^{\frac{1}{3}}

Solve separable ODE:

y = \frac{2 2 x ^{3} + c _{1}^{3} + 3 c _{1} x ^{2} + 3 c _{1}^{2} x}{3 3}, y = - \frac{2 2 x ^{3} + c _{1}^{3} + 3 c _{1} x ^{2} + 3 c _{1}^{2} x}{3 3}

y = \frac{2 2 x ^{3} + c _{1}^{3} + 3 c _{1} x ^{2} + 3 c _{1}^{2} x}{3 3}, y = - \frac{2 2 x ^{3} + c _{1}^{3} + 3 c _{1} x ^{2} + 3 c _{1}^{2} x}{3 3}

x^{2} + 11, at x = 5

t^{13 t}

\frac{d}{d x} (sec (5 x) + 1)

f (x) = 4 x^{\frac{5}{4}} + 4 x^{\frac{3}{2}} + 8 x

(x - 1)^{3} \frac{d y}{d x} + 4 (x - 1)^{2} y = x + 1

What is the solution for (dy)/(dx)=y^{1/3} ?
The solution for (dy)/(dx)=y^{1/3} is