What is (\partial)/(\partial x)(8^x) ?

The answer to (\partial)/(\partial x)(8^x) is 3ln(2)*8^x

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(\partial)/(\partial x)(8^x)

\frac{\partial}{\partial x} (8^{x})

3 ln (2) \cdot 8^{x}

Solution steps

\frac{\partial}{\partial x} (8^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= 8^{x} ln (8)

Simplify

ln (8) : 3 ln (2)

= 3 ln (2) \cdot 8^{x}

\int_{1}^{x} \frac{1}{1 + t ^{2}} d t

e^{x} (3 x^{2} - 5 x)

\frac{d y}{d x} = \frac{( - y ^{2} )}{( 1 + y ^{2} )} \cdot (e^{- x})

\frac{d}{d x} (- 2 sin (x) - x cos (x))

\int \frac{e ^{3 x}}{x} d x

What is (\partial)/(\partial x)(8^x) ?
The answer to (\partial)/(\partial x)(8^x) is 3ln(2)*8^x