What is implicit (dy)/(dx),x^2+y^2=4 ?

The answer to implicit (dy)/(dx),x^2+y^2=4 is (dy)/(dx)=-x/y

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implicit (dy)/(dx),x^2+y^2=4

implicit derivative

\frac{d y}{d x}, x^{2} + y^{2} = 4

\frac{d y}{d x} = - \frac{x}{y}

Solution steps

x^{2} + y^{2} = 4

Treat

y

y (x)

Differentiate both sides:

2 x + 2 y \frac{d y}{d x} = 0

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = - \frac{x}{y}

\frac{d y}{d x} = - \frac{x}{y}

y = lo g_{3} (8 x - 1)

\frac{d ^{2}}{d x ^{2}} (1 + x^{2})

y^{^{'}} + \frac{y}{6960} = 0.0025862069

\frac{d}{d x} (e^{(- x)})

\int 3 x d x

What is implicit (dy)/(dx),x^2+y^2=4 ?
The answer to implicit (dy)/(dx),x^2+y^2=4 is (dy)/(dx)=-x/y