What is the derivative of (log_{10}(x)/(ln(x))+2x) ?

The derivative of (log_{10}(x)/(ln(x))+2x) is 2

What is the first derivative of (log_{10}(x)/(ln(x))+2x) ?

The first derivative of (log_{10}(x)/(ln(x))+2x) is 2

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\frac{d}{d x} (\frac{lo g _{10} ( x )}{ln ( x )} + 2 x)

2

Solution steps

\frac{d}{d x} (\frac{lo g _{10} ( x )}{ln ( x )} + 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{lo g _{10} ( x )}{ln ( x )}) + \frac{d}{d x} (2 x)

\frac{d}{d x} (\frac{lo g _{10} ( x )}{ln ( x )}) = 0

\frac{d}{d x} (2 x) = 2

= 0 + 2

Simplify

= 2

y^{^{''}} + 5 y^{^{'}} + 6 y = 2 e^{x}

\frac{d}{d x} (in (sec (x)))

n = 1 \sum \infty \frac{2}{e ^{n - 3}}

y^{^{''}} - \frac{2}{x} y^{^{'}} - \frac{4}{x ^{2}} y = 3 x^{2}

x \to 1 + lim (x^{3} - 4)

What is the derivative of (log_{10}(x)/(ln(x))+2x) ?
The derivative of (log_{10}(x)/(ln(x))+2x) is 2
What is the first derivative of (log_{10}(x)/(ln(x))+2x) ?
The first derivative of (log_{10}(x)/(ln(x))+2x) is 2