What is the limit as h approaches 0 of ((1+h)^2-1)/h ?

The limit as h approaches 0 of ((1+h)^2-1)/h is 2

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limit as h approaches 0 of ((1+h)^2-1)/h

h \to 0 lim (\frac{( 1 + h ) ^{2} - 1}{h})

2

Solution steps

h \to 0 lim (\frac{( 1 + h ) ^{2} - 1}{h})

Simplify

\frac{( 1 + h ) ^{2} - 1}{h} : h + 2

= h \to 0 lim (h + 2)

Plug in the value

h = 0

= 0 + 2

Simplify

= 2

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What is the limit as h approaches 0 of ((1+h)^2-1)/h ?
The limit as h approaches 0 of ((1+h)^2-1)/h is 2