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Popular >

xy^'+y=3xy^2

Solution

x y^{^{'}} + y = 3 x y^{2}

Solution

y = \frac{1}{x ( - 3 ln ( x ) + c _{1} )}

Solution steps

x y^{'} (x) + y = 3 x y^{2}

Solve Bernoulli ODE:

y = \frac{1}{x ( - 3 ln ( x ) + c _{1} )}

y = \frac{1}{x ( - 3 ln ( x ) + c _{1} )}

Popular Examples

(\partial)/(\partial y)(x^2y+3xy^4)

\frac{\partial}{\partial y} (x^{2} y + 3 x y^{4})

derivative of 7x^{3/2}

\frac{d}{d x} (7 x^{\frac{3}{2}})

integral of x/(xln(x))

\int \frac{x}{x ln ( x )} d x

y^'=-y^2t-y^2t^2,y(0)=3

y^{^{'}} = - y^{2} t - y^{2} t^{2}, y (0) = 3

integral of sin(6x)sin(5x)

\int sin (6 x) sin (5 x) d x

Frequently Asked Questions (FAQ)

What is the solution for xy^'+y=3xy^2 ?
The solution for xy^'+y=3xy^2 is y= 1/(x(-3ln(x)+c_{1))}