What is the derivative of sin^3(2t) ?

The derivative of sin^3(2t) is 6sin^2(2t)cos(2t)

What is the first derivative of sin^3(2t) ?

The first derivative of sin^3(2t) is 6sin^2(2t)cos(2t)

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derivative of

sin^{3} (2 t)

6 sin^{2} (2 t) cos (2 t)

Solution steps

\frac{d}{d t} (sin^{3} (2 t))

Apply the chain rule:

3 (sin (2 t))^{2} \frac{d}{d t} (sin (2 t))

= 3 (sin (2 t))^{2} \frac{d}{d t} (sin (2 t))

\frac{d}{d t} (sin (2 t)) = cos (2 t) \cdot 2

= 3 (sin (2 t))^{2} cos (2 t) \cdot 2

Simplify

= 6 sin^{2} (2 t) cos (2 t)

f (x) = - 3 x^{2} + 4 x - 1

x \to 2 lim (\frac{( x ^{2} - 5 x + 4 )}{x - 2})

\int_{0}^{2} \frac{2 x}{( x ^{2} + 1 ) ^{2}} d x

\frac{\partial}{\partial x} (4 e^{5 x})

4 x + 6

What is the derivative of sin^3(2t) ?
The derivative of sin^3(2t) is 6sin^2(2t)cos(2t)
What is the first derivative of sin^3(2t) ?
The first derivative of sin^3(2t) is 6sin^2(2t)cos(2t)