What is the d/(dy)(e^x(x-y)^2) ?

The d/(dy)(e^x(x-y)^2) is -2e^x(x-y)

What is the first d/(dy)(e^x(x-y)^2) ?

The first d/(dy)(e^x(x-y)^2) is -2e^x(x-y)

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\frac{d}{d y} (e^{x} (x - y)^{2})

- 2 e^{x} (x - y)

Solution steps

\frac{d}{d y} (e^{x} (x - y)^{2})

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= e^{x} \frac{d}{d y} ((x - y)^{2})

Apply the chain rule:

2 (x - y) \frac{d}{d y} (x - y)

= 2 (x - y) \frac{d}{d y} (x - y)

\frac{d}{d y} (x - y) = - 1

= e^{x} \cdot 2 (x - y) (- 1)

Simplify

= - 2 e^{x} (x - y)

\frac{\partial}{\partial x} (cos^{3} (x))

\int (4 x^{2} - 2) d x

\frac{\partial}{\partial y} (\frac{4 x}{3 y ^{2} + 1})

x \to 2 lim (3 + x)

\frac{d}{d x} (\frac{e ^{x}}{7 x ^{2}})

What is the d/(dy)(e^x(x-y)^2) ?
The d/(dy)(e^x(x-y)^2) is -2e^x(x-y)
What is the first d/(dy)(e^x(x-y)^2) ?
The first d/(dy)(e^x(x-y)^2) is -2e^x(x-y)