What is the derivative of f(x)=(x^2-5)e^x ?

The derivative of f(x)=(x^2-5)e^x is 2xe^x+e^x(x^2-5)

What is the first derivative of f(x)=(x^2-5)e^x ?

The first derivative of f(x)=(x^2-5)e^x is 2xe^x+e^x(x^2-5)

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derivative of

f (x) = (x^{2} - 5) e^{x}

2 x e^{x} + e^{x} (x^{2} - 5)

Solution steps

\frac{d}{d x} ((x^{2} - 5) e^{x})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2} - 5, g = e^{x}

= \frac{d}{d x} (x^{2} - 5) e^{x} + \frac{d}{d x} (e^{x}) (x^{2} - 5)

\frac{d}{d x} (x^{2} - 5) = 2 x

\frac{d}{d x} (e^{x}) = e^{x}

= 2 x e^{x} + e^{x} (x^{2} - 5)

\frac{\partial}{\partial y} (1)

\frac{d x}{d t} = 5 x (8 - x)

\frac{d}{d x} (sin (5 x) ln (sin^{2} (5 x)))

\frac{10}{s ^{3} + 2 s ^{2} + 20 s}

\int_{0}^{1} 0 d x

What is the derivative of f(x)=(x^2-5)e^x ?
The derivative of f(x)=(x^2-5)e^x is 2xe^x+e^x(x^2-5)
What is the first derivative of f(x)=(x^2-5)e^x ?
The first derivative of f(x)=(x^2-5)e^x is 2xe^x+e^x(x^2-5)