What is the derivative of x^2-y ?

The derivative of x^2-y is 2x-(dy)/(dx)

What is the first derivative of x^2-y ?

The first derivative of x^2-y is 2x-(dy)/(dx)

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\frac{d}{d x} (x^{2} - y)

2 x - \frac{d y}{d x}

Solution steps

\frac{d}{d x} (x^{2} - y)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d y}{d x}

\frac{d}{d x} (x^{2}) = 2 x

= 2 x - \frac{d y}{d x}

\int \frac{x ^{2}}{( x ^{2} + 6 )} d x

y = (4 x^{2} + 5) (5 x - 3)

(3 x^{2} - 3 x + 1) (x^{3})

\int \frac{1}{( 4 + x ^{2} ) ^{\frac{5}{2}}} d x

\int \frac{( 5 + ln ( x ) ) ^{5}}{x} d x

What is the derivative of x^2-y ?
The derivative of x^2-y is 2x-(dy)/(dx)
What is the first derivative of x^2-y ?
The first derivative of x^2-y is 2x-(dy)/(dx)