What is laplacetransform 10+t^2 ?

The answer to laplacetransform 10+t^2 is (10)/s+2/(s^3)

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laplacetransform 10+t^2

laplace transform

10 + t^{2}

\frac{10}{s} + \frac{2}{s ^{3}}

Solution steps

L {10 + t^{2}}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= L {10} + L {t^{2}}

L {10} : \frac{10}{s}

L {t^{2}} : \frac{2}{s ^{3}}

= \frac{10}{s} + \frac{2}{s ^{3}}

\frac{\partial}{\partial y} (6 x^{2})

\int \frac{6 + x ^{2}}{x} d x

(x + 1) (7 x + 2)

\frac{\partial}{\partial x} (\frac{x}{y ^{2}} + x y + 8)

\frac{d}{d x} (ln (\frac{( 2 x + 1 ) ^{3}}{( 3 x - 1 ) ^{4}}))

What is laplacetransform 10+t^2 ?
The answer to laplacetransform 10+t^2 is (10)/s+2/(s^3)