What is the tangent of y=8x+12-15e^x,(0,-3) ?

The tangent of y=8x+12-15e^x,(0,-3) is y=-7x-3

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tangent of y=8x+12-15e^x,(0,-3)

tangent of

y = 8 x + 12 - 15 e^{x}, (0, - 3)

y = - 7 x - 3

Solution steps

Find the slope of

y = 8 x + 12 - 15 e^{x} : \frac{d y}{d x} = - 15 e^{x} + 8

Compute the slope of

y = 8 x + 12 - 15 e^{x}

(0, - 3) : m = - 7

Find the line with slope m=

- 7

and passing through

(0, - 3) : y = - 7 x - 3

y = - 7 x - 3

\int \frac{3 + x}{1 + x ^{2}} d x

x^{2} + 10, 9 x, 0

\int \frac{( 9 - y ^{2} ) ^{2}}{2} - y (9 - y^{2}) d y

\int y + 4 d y

\frac{d}{d x} (\frac{2 x}{x ^{4} + 1})

What is the tangent of y=8x+12-15e^x,(0,-3) ?
The tangent of y=8x+12-15e^x,(0,-3) is y=-7x-3