What is inverse oflaplace e^{-,\at} ?

The answer to inverse oflaplace e^{-,\at} is e^{-,\at}\delta(t)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse oflaplace e^{-,\at}

inverse laplace

e^{-, at}

e^{-, at} δ (t)

Solution steps

L^{- 1} {e^{-, at}}

= L^{- 1} {e^{-, at} \cdot 1}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= e^{-, at} L^{- 1} {1}

Use Inverse Laplace Transform table:

L^{- 1} {1} = δ (t)

Where

δ (t)

is Dirac delta function

= e^{-, at} δ (t)

\int \frac{4}{3 - e ^{x}} d x

x^{2} + 2 x + 11, - 4 x + 2, [0]

\int \frac{3}{1 - x ^{2}} d x

\frac{\partial}{\partial x} (x^{4} + y^{4} - 4 x^{2} y^{2})

\frac{\partial}{\partial y} (\frac{y}{x ^{2} y ^{2} + 1})

What is inverse oflaplace e^{-,\at} ?
The answer to inverse oflaplace e^{-,\at} is e^{-,\at}\delta(t)