What is the derivative of f(x)=1-4x^2 ?

The derivative of f(x)=1-4x^2 is -8x

What is the first derivative of f(x)=1-4x^2 ?

The first derivative of f(x)=1-4x^2 is -8x

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derivative of

f (x) = 1 - 4 x^{2}

- 8 x

Solution steps

\frac{d}{d x} (1 - 4 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) - \frac{d}{d x} (4 x^{2})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (4 x^{2}) = 8 x

= 0 - 8 x

Simplify

= - 8 x

\frac{d y}{d x} = y (0.1 - 1 0^{- 7} y)

\frac{d}{d x} (ln ∣ x - 1 ∣ - ln ∣ x - 3 ∣)

\int arccsc (\frac{t}{2}) d t

x \to 2 lim (x^{2})

(7 a + 1)^{2}

What is the derivative of f(x)=1-4x^2 ?
The derivative of f(x)=1-4x^2 is -8x
What is the first derivative of f(x)=1-4x^2 ?
The first derivative of f(x)=1-4x^2 is -8x