What is the derivative of e^6+ln(9) ?

The derivative of e^6+ln(9) is 0

What is the first derivative of e^6+ln(9) ?

The first derivative of e^6+ln(9) is 0

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\frac{d}{d x} (e^{6} + ln (9))

0

Solution steps

\frac{d}{d x} (e^{6} + ln (9))

e^{6} + ln (9) = e^{6} + 2 ln (3)

= \frac{d}{d x} (e^{6} + 2 ln (3))

Derivative of a constant:

\frac{d}{d x} (a) = 0

= 0

f (x)^{8} x^{2} + 4 x - 7, x = - 3

\int sec^{2} (x t a) n^{5} x d x

(\frac{1}{y ^{2}} - \frac{5}{y ^{4}}) (y + 3 y^{3})

x \to 3 + lim (18 ln (x - 3))

\frac{d}{d x} (e^{5})

What is the derivative of e^6+ln(9) ?
The derivative of e^6+ln(9) is 0
What is the first derivative of e^6+ln(9) ?
The first derivative of e^6+ln(9) is 0