What is the derivative of y=2e^{-x}+e^{3x} ?

The derivative of y=2e^{-x}+e^{3x} is -2e^{-x}+e^{3x}*3

What is the first derivative of y=2e^{-x}+e^{3x} ?

The first derivative of y=2e^{-x}+e^{3x} is -2e^{-x}+e^{3x}*3

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derivative of

y = 2 e^{- x} + e^{3 x}

- 2 e^{- x} + e^{3 x} \cdot 3

Solution steps

\frac{d}{d x} (2 e^{- x} + e^{3 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 e^{- x}) + \frac{d}{d x} (e^{3 x})

\frac{d}{d x} (2 e^{- x}) = - 2 e^{- x}

\frac{d}{d x} (e^{3 x}) = e^{3 x} \cdot 3

= - 2 e^{- x} + e^{3 x} \cdot 3

n = 1 \sum \infty \frac{n}{4 n ^{3} + 1}

h (x) = sec^{6} (x)

\int \frac{e ^{x}}{1 - 25 e ^{2 x}} d x

\frac{\partial}{\partial x} (\frac{x}{x ^{2} + y ^{2}})

\frac{d}{d x} (3 sin^{3} (x))

What is the derivative of y=2e^{-x}+e^{3x} ?
The derivative of y=2e^{-x}+e^{3x} is -2e^{-x}+e^{3x}*3
What is the first derivative of y=2e^{-x}+e^{3x} ?
The first derivative of y=2e^{-x}+e^{3x} is -2e^{-x}+e^{3x}*3