What is (\partial)/(\partial y)(8x-(x+y)^3) ?

The answer to (\partial)/(\partial y)(8x-(x+y)^3) is -3x^2-6xy-3y^2

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(\partial)/(\partial y)(8x-(x+y)^3)

\frac{\partial}{\partial y} (8 x - (x + y)^{3})

- 3 x^{2} - 6 x y - 3 y^{2}

Solution steps

\frac{\partial}{\partial y} (8 x - (x + y)^{3})

Simplify

8 x - (x + y)^{3} : 8 x - x^{3} - 3 x^{2} y - 3 x y^{2} - y^{3}

= \frac{\partial}{\partial y} (8 x - x^{3} - 3 x^{2} y - 3 x y^{2} - y^{3})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (8 x) - \frac{\partial}{\partial y} (x^{3}) - \frac{\partial}{\partial y} (3 x^{2} y) - \frac{\partial}{\partial y} (3 x y^{2}) - \frac{\partial}{\partial y} (y^{3})

\frac{\partial}{\partial y} (8 x) = 0

\frac{\partial}{\partial y} (x^{3}) = 0

\frac{\partial}{\partial y} (3 x^{2} y) = 3 x^{2}

\frac{\partial}{\partial y} (3 x y^{2}) = 6 x y

\frac{\partial}{\partial y} (y^{3}) = 3 y^{2}

= 0 - 0 - 3 x^{2} - 6 x y - 3 y^{2}

Simplify

= - 3 x^{2} - 6 x y - 3 y^{2}

\frac{d}{d x} (\frac{1}{x ^{31}})

(\frac{2}{x} - 1)^{- 1}

x \to 0 lim (ln (\frac{x}{3}) + x^{2} - 8)

\frac{2}{3} t^{3} e^{- 8 t}

\frac{d}{d x} (3 cos (x) - sin (x))

What is (\partial)/(\partial y)(8x-(x+y)^3) ?
The answer to (\partial)/(\partial y)(8x-(x+y)^3) is -3x^2-6xy-3y^2