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Popular >

y^'-y=1,y(0)=1

Solution

y^{^{'}} - y = 1, y (0) = 1

Solution

y = 2 e^{t} - 1

Solution steps

y^{'} (t) - y = 1

Solve separable ODE:

y = 2 e^{t} - 1

y = 2 e^{t} - 1

Popular Examples

integral of sin^3(18x)cos^3(18x)

\int sin^{3} (18 x) cos^{3} (18 x) d x

integral of (8x)/((1-x^2)^4)

\int \frac{8 x}{( 1 - x ^{2} ) ^{4}} d x

(\partial)/(\partial z)((4x-4z)/(y+4z))

\frac{\partial}{\partial z} (\frac{4 x - 4 z}{y + 4 z})

y y^{^{'}} = x - 2 x^{3}

derivative of a^7+(cos(x)^7)

\frac{d}{d x} (a^{7} + (cos (x))^{7})

Frequently Asked Questions (FAQ)

What is the solution for y^'-y=1,y(0)=1 ?
The solution for y^'-y=1,y(0)=1 is y=2e^t-1