What is the sum from n=1 to infinity of 8-7(0.8)^n ?

The sum from n=1 to infinity of 8-7(0.8)^n is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=1 to infinity of 8-7(0.8)^n

n = 1 \sum \infty 8 - 7 (0.8)^{n}

diverges

Solution steps

n = 1 \sum \infty 8 - 7 \cdot 0. 8^{n}

Apply Series Divergence Test:

diverges

= diverges

x \to 17 lim (3 x + 2)

y = (3 x^{2} + 5)^{4}

y^{^{'}} + x e^{\frac{- x ^{2}}{2}} = 0

\frac{d}{d x} (x + y) = 4

\frac{d y}{d x} = e^{y - 2 x}

What is the sum from n=1 to infinity of 8-7(0.8)^n ?
The sum from n=1 to infinity of 8-7(0.8)^n is diverges