What is the limit as x approaches-3 of (x^2)/(x^2-9) ?

The limit as x approaches-3 of (x^2)/(x^2-9) is diverges

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limit as x approaches-3 of (x^2)/(x^2-9)

x \to - 3 lim (\frac{x ^{2}}{x ^{2} - 9})

diverges

Solution steps

x \to - 3 lim (\frac{x ^{2}}{x ^{2} - 9})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - 3 + lim (\frac{x ^{2}}{x ^{2} - 9}) = - \infty

x \to - 3 - lim (\frac{x ^{2}}{x ^{2} - 9}) = \infty

= diverges

\frac{\partial}{\partial x} (x sin (x^{2} - y^{2}))

(x + y e^{\frac{y}{x}}) d x - (x e^{\frac{y}{x}}) d y = 0

\frac{d}{d x} (\frac{- x ^{2} - 5}{( x ^{2} - 5 ) ^{2}})

\int e^{2 x} - x e^{2 x} d x

\frac{d}{d x} (- 7 csc (x) + \frac{1}{x ^{5}})

What is the limit as x approaches-3 of (x^2)/(x^2-9) ?
The limit as x approaches-3 of (x^2)/(x^2-9) is diverges