What is laplacetransform sin(2t+3) ?

The answer to laplacetransform sin(2t+3) is (sin(3)s+2cos(3))/(s^2+4)

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laplacetransform sin(2t+3)

laplace transform

sin (2 t + 3)

\frac{sin ( 3 ) s + 2 cos ( 3 )}{s ^{2} + 4}

Solution steps

L {sin (2 t + 3)}

Use Laplace Transform table:

L {sin (a t + b)} = \frac{s \cdot sin ( b ) + a \cdot cos ( b )}{s ^{2} + a ^{2}}

L {sin (2 t + 3)} = \frac{s sin ( 3 ) + 2 cos ( 3 )}{s ^{2} + 2 ^{2}}

= \frac{s sin ( 3 ) + 2 cos ( 3 )}{s ^{2} + 2 ^{2}}

= \frac{sin ( 3 ) s + 2 cos ( 3 )}{s ^{2} + 4}

y = x, x \geq 0

\int \frac{1}{x 5 x ^{2} - 3} d x

6 sin (2 x)

\int x^{5} sin (2 x) d x

\frac{d}{d x} (\frac{1}{1 + c e ^{- x}})

What is laplacetransform sin(2t+3) ?
The answer to laplacetransform sin(2t+3) is (sin(3)s+2cos(3))/(s^2+4)