What is the solution for t(dy)/(dt)+30y= 1/t ?

The solution for t(dy)/(dt)+30y= 1/t is y= 1/(29t)+(c_{1})/(t^{30)}

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t(dy)/(dt)+30y= 1/t

t \frac{d y}{d t} + 30 y = \frac{1}{t}

y = \frac{1}{29 t} + \frac{c _{1}}{t ^{30}}

Solution steps

t \frac{d y}{d t} + 30 y = \frac{1}{t}

Solve linear ODE:

y = \frac{1}{29 t} + \frac{c _{1}}{t ^{30}}

y = \frac{1}{29 t} + \frac{c _{1}}{t ^{30}}

\int x e^{\frac{x}{2}} d x

(8.4) (5.2)

\int - \frac{3000}{x ^{2}} d x

\int \frac{10 x}{4 x ^{2} - 4} d x

\frac{( s + 3 )}{( s + 7 )}

What is the solution for t(dy)/(dt)+30y= 1/t ?
The solution for t(dy)/(dt)+30y= 1/t is y= 1/(29t)+(c_{1})/(t^{30)}