What is the derivative of 3sin(3x) ?

The derivative of 3sin(3x) is 9cos(3x)

What is the first derivative of 3sin(3x) ?

The first derivative of 3sin(3x) is 9cos(3x)

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derivative of

3 sin (3 x)

9 cos (3 x)

Solution steps

\frac{d}{d x} (3 sin (3 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (sin (3 x))

Apply the chain rule:

cos (3 x) \frac{d}{d x} (3 x)

= cos (3 x) \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x) = 3

= 3 cos (3 x) \cdot 3

Simplify

= 9 cos (3 x)

\int \frac{x ^{4} - 6 x ^{3} + 12 x ^{2} + 6}{x ^{3} - 6 x ^{2} + 12 x - 8} d x

\frac{d}{d x} (\frac{( x + 4 ) ( x ^{2} - 4 x + 16 )}{x ^{3}})

5 x sin (x)

\int e^{- x} - 1 d x

\frac{\partial}{\partial x} (- x^{2})

What is the derivative of 3sin(3x) ?
The derivative of 3sin(3x) is 9cos(3x)
What is the first derivative of 3sin(3x) ?
The first derivative of 3sin(3x) is 9cos(3x)