What is the tangent of y=2x^4,(-2,32) ?

The tangent of y=2x^4,(-2,32) is y=-64x-96

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tangent of y=2x^4,(-2,32)

tangent of

y = 2 x^{4}, (- 2, 32)

y = - 64 x - 96

Solution steps

Find the slope of

y = 2 x^{4} : \frac{d y}{d x} = 8 x^{3}

Compute the slope of

y = 2 x^{4}

(- 2, 32) : m = - 64

Find the line with slope m=

- 64

and passing through

(- 2, 32) : y = - 64 x - 96

y = - 64 x - 96

x \to 2 lim (- x)

\frac{d}{d x} (\frac{5 x ^{2} + 25 x}{5 x})

\int 10 - x^{2} d x

\int (x e^{- x^{2}}) d x

y = ln 5 + t - t^{3}

What is the tangent of y=2x^4,(-2,32) ?
The tangent of y=2x^4,(-2,32) is y=-64x-96