What is the d/(dt)(sqrt(t-1)) ?

The d/(dt)(sqrt(t-1)) is 1/(2sqrt(t-1))

What is the first d/(dt)(sqrt(t-1)) ?

The first d/(dt)(sqrt(t-1)) is 1/(2sqrt(t-1))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d t} (t - 1)

\frac{1}{2 t - 1}

Solution steps

\frac{d}{d t} (t - 1)

Apply the chain rule:

\frac{1}{2 t - 1} \frac{d}{d t} (t - 1)

= \frac{1}{2 t - 1} \frac{d}{d t} (t - 1)

\frac{d}{d t} (t - 1) = 1

= \frac{1}{2 t - 1} \cdot 1

Simplify

= \frac{1}{2 t - 1}

f (x) = 645120

\int_{- \infty}^{0} z e^{4 z} d z

f (x) = (x - 5)^{5}, at x = 6

x + \frac{1}{x ^{2}}

\int \frac{x ^{3}}{x ^{2} - 2 x + 1} d x

What is the d/(dt)(sqrt(t-1)) ?
The d/(dt)(sqrt(t-1)) is 1/(2sqrt(t-1))
What is the first d/(dt)(sqrt(t-1)) ?
The first d/(dt)(sqrt(t-1)) is 1/(2sqrt(t-1))