What is the derivative of 3x^2+8x+5 ?

The derivative of 3x^2+8x+5 is 6x+8

What is the first derivative of 3x^2+8x+5 ?

The first derivative of 3x^2+8x+5 is 6x+8

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\frac{d}{d x} (3 x^{2} + 8 x + 5)

6 x + 8

Solution steps

\frac{d}{d x} (3 x^{2} + 8 x + 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (8 x) + \frac{d}{d x} (5)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (5) = 0

= 6 x + 8 + 0

Simplify

= 6 x + 8

\frac{\partial}{\partial y} (6 x y - 5 y)

- 10 x + 11, x^{2} - 5 x - 13, - 8, 3

x \to 0 lim (\frac{7}{x} - 7 cot (x))

f (x) = \frac{x}{7 + x}

What is the derivative of 3x^2+8x+5 ?
The derivative of 3x^2+8x+5 is 6x+8
What is the first derivative of 3x^2+8x+5 ?
The first derivative of 3x^2+8x+5 is 6x+8