What is the integral of 3^xsin(x) ?

The integral of 3^xsin(x) is -(3^xcos(x))/(1+ln^2(3))+(ln(3)*3^xsin(x))/(1+ln^2(3))+C

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integral of 3^xsin(x)

\int 3^{x} sin (x) d x

- \frac{3 ^{x} cos ( x )}{1 + ln ^{2} ( 3 )} + \frac{ln ( 3 ) \cdot 3 ^{x} sin ( x )}{1 + ln ^{2} ( 3 )} + C

Solution steps

\int 3^{x} sin (x) d x

Apply Integration By Parts

: - 3^{x} cos (x) - \int - ln (3) \cdot 3^{x} cos (x) d x

= - 3^{x} cos (x) - \int - ln (3) \cdot 3^{x} cos (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 3^{x} cos (x) - (- ln (3) \cdot \int 3^{x} cos (x) d x)

Apply Integration By Parts

: 3^{x} sin (x) - \int 3^{x} ln (3) sin (x) d x

= - 3^{x} cos (x) - (- ln (3) (3^{x} sin (x) - \int 3^{x} ln (3) sin (x) d x))

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 3^{x} cos (x) - (- ln (3) (3^{x} sin (x) - ln (3) \cdot \int 3^{x} sin (x) d x))

Therefore

\int 3^{x} sin (x) d x = - 3^{x} cos (x) - (- ln (3) (3^{x} sin (x) - ln (3) \cdot \int 3^{x} sin (x) d x))

Isolate

\int 3^{x} sin (x) d x

= - \frac{3 ^{x} cos ( x )}{1 + ln ^{2} ( 3 )} + \frac{ln ( 3 ) \cdot 3 ^{x} sin ( x )}{1 + ln ^{2} ( 3 )}

Add a constant to the solution

= - \frac{3 ^{x} cos ( x )}{1 + ln ^{2} ( 3 )} + \frac{ln ( 3 ) \cdot 3 ^{x} sin ( x )}{1 + ln ^{2} ( 3 )} + C

\frac{\partial}{\partial y} (y cos (x ln (y)))

\int_{0}^{2} 1 + 3 x^{2} d x

6 x^{- 3}, at x = 5

\frac{x - y}{x + y}

\frac{d}{d x} (\frac{x ^{2}}{x})

What is the integral of 3^xsin(x) ?
The integral of 3^xsin(x) is -(3^xcos(x))/(1+ln^2(3))+(ln(3)*3^xsin(x))/(1+ln^2(3))+C