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Popular >

y^'=e^{2y+6x}

Solution

y^{^{'}} = e^{2 y + 6 x}

Solution

y = - \frac{ln ( - \frac{1}{3} e ^{6 x} - c _{1} )}{2}

Solution steps

y^{'} (x) = e^{2 y + 6 x}

Solve separable ODE:

y = - \frac{ln ( - \frac{1}{3} e ^{6 x} - c _{1} )}{2}

y = - \frac{ln ( - \frac{1}{3} e ^{6 x} - c _{1} )}{2}

Popular Examples

integral of (8x^3+8x^2+8)/(x^2+x)

\int \frac{8 x ^{3} + 8 x ^{2} + 8}{x ^{2} + x} d x

integral of (xln(x))/x

\int \frac{x ln ( x )}{x} d x

tangent of f(x)= 1/(x^5),(2, 1/32)tangent of

f (x) = \frac{1}{x ^{5}}, (2, \frac{1}{32})

derivative of f(t)=sqrt(2t^2-t)derivative of

f (t) = 2 t^{2} - t

y^'+1/(x+1)y=x^{-2}

y^{^{'}} + \frac{1}{x + 1} y = x^{- 2}

Frequently Asked Questions (FAQ)

What is the solution for y^'=e^{2y+6x} ?
The solution for y^'=e^{2y+6x} is y=-(ln(-1/3 e^{6x}-c_{1}))/2