What is the tangent of f(x)=(3x-2)(x+4),(1,5) ?

The tangent of f(x)=(3x-2)(x+4),(1,5) is y=16x-11

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tangent of f(x)=(3x-2)(x+4),(1,5)

tangent of

f (x) = (3 x - 2) (x + 4), (1, 5)

y = 16 x - 11

Solution steps

Find the slope of

f (x) = (3 x - 2) (x + 4) : \frac{df ( x )}{d x} = 6 x + 10

Compute the slope of

f (x) = (3 x - 2) (x + 4)

(1, 5) : m = 16

Find the line with slope m=

16

and passing through

(1, 5) : y = 16 x - 11

y = 16 x - 11

\frac{\partial}{\partial y} (x \cdot cos (y) \cdot sin (z))

x \to \infty lim (\frac{- x}{x})

\int \frac{( 3 x - 5 )}{x ^{2} + 4 x} d x

f (x) = 3 x^{2} - 7

\int e^{x} sinh (x) d x

What is the tangent of f(x)=(3x-2)(x+4),(1,5) ?
The tangent of f(x)=(3x-2)(x+4),(1,5) is y=16x-11