What is the derivative of 2x-0.1x^2 ?

The derivative of 2x-0.1x^2 is 2-0.2x

What is the first derivative of 2x-0.1x^2 ?

The first derivative of 2x-0.1x^2 is 2-0.2x

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\frac{d}{d x} (2 x - 0.1 x^{2})

2 - 0.2 x

Solution steps

\frac{d}{d x} (2 x - 0.1 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) - \frac{d}{d x} (0.1 x^{2})

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (0.1 x^{2}) = 0.2 x

= 2 - 0.2 x

y = 9 + 4 x^{2} - 2 x^{3}, (1, 11)

\frac{d}{d x} (\frac{9}{ln ( x )})

\int - 4 t d t

f (x) = - 1 - x x^{2}

\int cos (22 x) cos (17 x) d x

What is the derivative of 2x-0.1x^2 ?
The derivative of 2x-0.1x^2 is 2-0.2x
What is the first derivative of 2x-0.1x^2 ?
The first derivative of 2x-0.1x^2 is 2-0.2x