What is (\partial)/(\partial x)(2x+1) ?

The answer to (\partial)/(\partial x)(2x+1) is 2

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(\partial)/(\partial x)(2x+1)

\frac{\partial}{\partial x} (2 x + 1)

2

Solution steps

\frac{\partial}{\partial x} (2 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x) + \frac{\partial}{\partial x} (1)

\frac{\partial}{\partial x} (2 x) = 2

\frac{\partial}{\partial x} (1) = 0

= 2 + 0

Simplify

= 2

\frac{\partial}{\partial z} (z cos (x z))

\int_{1}^{2} 2 r^{2} ln (r) d r

\int 0.75 e d k

\int \frac{1}{x} - 1 \frac{1}{x ^{2}} d x

\frac{4}{s ( s ^{2} + s )}

What is (\partial)/(\partial x)(2x+1) ?
The answer to (\partial)/(\partial x)(2x+1) is 2