What is the derivative of se^{-sx{y}(s,x}) ?

The derivative of se^{-sx{y}(s,x}) is se^{-sx{y}(s,x)}(-s(1*{y}(s,x)+derivative of {y}(s,x)x))

What is the first derivative of se^{-sx{y}(s,x}) ?

The first derivative of se^{-sx{y}(s,x}) is se^{-sx{y}(s,x)}(-s(1*{y}(s,x)+derivative of {y}(s,x)x))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (s e^{- s x y (s, x)})

s e^{- s x y (s, x)} (- s (1 \cdot y (s, x) + \frac{d}{d x} (y (s, x)) x))

Solution steps

\frac{d}{d x} (s e^{- s x y (s, x)})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= s \frac{d}{d x} (e^{- s x y (s, x)})

Apply the chain rule:

e^{- s x y (s, x)} \frac{d}{d x} (- s x y (s, x))

= e^{- s x y (s, x)} \frac{d}{d x} (- s x y (s, x))

\frac{d}{d x} (- s x y (s, x)) = - s (1 \cdot y (s, x) + \frac{d}{d x} (y (s, x)) x)

= s e^{- s x y (s, x)} (- s (1 \cdot y (s, x) + \frac{d}{d x} (y (s, x)) x))

\int \frac{x + 1}{x ^{3} - x ^{2}} d x

\int_{0}^{π} sin^{2} (x) d x

\frac{\partial}{\partial x} (ln (4 - x^{2}))

y = 4 x^{2} - x^{3}, (1, 3)

(0.1) (1.1)

What is the derivative of se^{-sx{y}(s,x}) ?
The derivative of se^{-sx{y}(s,x}) is se^{-sx{y}(s,x)}(-s(1*{y}(s,x)+derivative of {y}(s,x)x))
What is the first derivative of se^{-sx{y}(s,x}) ?
The first derivative of se^{-sx{y}(s,x}) is se^{-sx{y}(s,x)}(-s(1*{y}(s,x)+derivative of {y}(s,x)x))