What is the d/(dθ)(θ-sin(θ)) ?

The d/(dθ)(θ-sin(θ)) is 1-cos(θ)

What is the first d/(dθ)(θ-sin(θ)) ?

The first d/(dθ)(θ-sin(θ)) is 1-cos(θ)

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\frac{d}{d θ} (θ - sin (θ))

1 - cos (θ)

Solution steps

\frac{d}{d θ} (θ - sin (θ))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d θ} (θ) - \frac{d}{d θ} (sin (θ))

\frac{d}{d θ} (θ) = 1

\frac{d}{d θ} (sin (θ)) = cos (θ)

= 1 - cos (θ)

x \to 0 lim (\frac{1}{sin ( x )})

\frac{\partial}{\partial x} (\frac{y}{( x + y ) ^{2}})

\frac{d}{d x} (6 x^{2} - x^{3})

7 x^{2} - x^{3}

\frac{\partial}{\partial y} (x^{2} e^{- y})