What is (\partial)/(\partial x)(xsin(y)+ze^x) ?

The answer to (\partial)/(\partial x)(xsin(y)+ze^x) is sin(y)+ze^x

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(\partial)/(\partial x)(xsin(y)+ze^x)

\frac{\partial}{\partial x} (x sin (y) + z e^{x})

sin (y) + z e^{x}

Solution steps

\frac{\partial}{\partial x} (x sin (y) + z e^{x})

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x sin (y)) + \frac{\partial}{\partial x} (z e^{x})

\frac{\partial}{\partial x} (x sin (y)) = sin (y)

\frac{\partial}{\partial x} (z e^{x}) = z e^{x}

= sin (y) + z e^{x}

\int (6 x - 7) d x

f (x) = \frac{1 - 2 ln ( x )}{x ^{3}}

sin (3 x^{2})

e^{x}, e^{- 2 x}, x = ln (3)

x = y^{4}, y = 2 - x, y = 0

What is (\partial)/(\partial x)(xsin(y)+ze^x) ?
The answer to (\partial)/(\partial x)(xsin(y)+ze^x) is sin(y)+ze^x