What is the tangent of f(x)=2x^2+x-2,\at x=4 ?

The tangent of f(x)=2x^2+x-2,\at x=4 is y=17x-34

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=2x^2+x-2,\at x=4

tangent of

f (x) = 2 x^{2} + x - 2, at x = 4

y = 17 x - 34

Solution steps

Find the tangent point:

(4, 34)

Find the slope of

f (x) = 2 x^{2} + x - 2 : \frac{df ( x )}{d x} = 4 x + 1

Compute the slope of

f (x) = 2 x^{2} + x - 2

x = 4 : m = 17

Find the line with slope m=

17

and passing through

(4, 34) : y = 17 x - 34

y = 17 x - 34

\int \frac{- 1600 x}{25 - x ^{2}} d x

\int \frac{1}{x 8 x + 81} d x

\frac{\partial}{\partial x} (x + e^{y})

\frac{\partial}{\partial x} (4 x + 8 y - 88)

f (x) = - x^{\frac{2}{3}} (x - 5)

What is the tangent of f(x)=2x^2+x-2,\at x=4 ?
The tangent of f(x)=2x^2+x-2,\at x=4 is y=17x-34