What is the integral from-1 to 0 of x^3 ?

The integral from-1 to 0 of x^3 is -1/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-1 to 0 of x^3

\int_{- 1}^{0} x^{3} d x

- \frac{1}{4}

Decimal Notation

- 0.25

Solution steps

\int_{- 1}^{0} x^{3} d x

Apply the Power Rule

: [\frac{x ^{4}}{4}]_{- 1}^{0}

= [\frac{x ^{4}}{4}]_{- 1}^{0}

Compute the boundaries:

- \frac{1}{4}

= - \frac{1}{4}

- \frac{32}{x ^{3}} + \frac{4}{x ^{2}}

(1 + y e^{x y}) d x + (4 + x e^{x y}) d y = 0

\frac{d}{d x} ((arctan (2 x))^{10})

\int_{6}^{7} t t - 6 d t

\int \frac{1}{( 2 x - 9 ) ^{4}} d x

What is the integral from-1 to 0 of x^3 ?
The integral from-1 to 0 of x^3 is -1/4