What is the solution for y^'+1/t y=3cos(2t) ?

The solution for y^'+1/t y=3cos(2t) is y=(3(2tsin(2t)+cos(2t))}{4t}+\frac{c_{1})/t

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y^'+1/t y=3cos(2t)

y^{^{'}} + \frac{1}{t} y = 3 cos (2 t)

y = \frac{3 ( 2 t sin ( 2 t ) + cos ( 2 t ) )}{4 t} + \frac{c _{1}}{t}

Solution steps

y^{'} (t) + \frac{1}{t} y = 3 cos (2 t)

Solve linear ODE:

y = \frac{3 ( 2 t sin ( 2 t ) + cos ( 2 t ) )}{4 t} + \frac{c _{1}}{t}

y = \frac{3 ( 2 t sin ( 2 t ) + cos ( 2 t ) )}{4 t} + \frac{c _{1}}{t}

\frac{d}{d x} (x^{2} cos (ln (x)))

x \to 0 + lim (x \cdot e^{\frac{1}{x}})

\int \frac{x}{1 - 3 x ^{2}} d x

\int 5 cot^{5} (x) sin^{4} (x) d x

\int t 2 t^{2} + 3 d t

What is the solution for y^'+1/t y=3cos(2t) ?
The solution for y^'+1/t y=3cos(2t) is y=(3(2tsin(2t)+cos(2t))}{4t}+\frac{c_{1})/t