What is the limit as x approaches 4 of 5/((x-4)^2) ?

The limit as x approaches 4 of 5/((x-4)^2) is infinity

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limit as x approaches 4 of 5/((x-4)^2)

x \to 4 lim (\frac{5}{( x - 4 ) ^{2}})

\infty

Solution steps

x \to 4 lim (\frac{5}{( x - 4 ) ^{2}})

x \to a - lim f (x) = x \to a + lim f (x) = L

then

x \to a lim f (x) = L

x \to 4 - lim (\frac{5}{( x - 4 ) ^{2}}) = \infty

x \to 4 + lim (\frac{5}{( x - 4 ) ^{2}}) = \infty

= \infty

\frac{d}{d x} (2 cos (x) - 3 ln (x) - 1)

\frac{d y}{d x}, y^{4} = 2 x

\int_{0}^{\infty} x y e^{- y x} d x

\frac{14}{2 x + 16}

x y^{3} d y = d x, y (1) = 2

What is the limit as x approaches 4 of 5/((x-4)^2) ?
The limit as x approaches 4 of 5/((x-4)^2) is infinity