What is the derivative of x^{1/11}(x-1^2) ?

The derivative of x^{1/11}(x-1^2) is (23x^2-24x+1)/(11x^{10/11)}

What is the first derivative of x^{1/11}(x-1^2) ?

The first derivative of x^{1/11}(x-1^2) is (23x^2-24x+1)/(11x^{10/11)}

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\frac{d}{d x} (x^{\frac{1}{11}} (x - 1)^{2})

\frac{23 x ^{2} - 24 x + 1}{11 x ^{\frac{10}{11}}}

Solution steps

\frac{d}{d x} (x^{\frac{1}{11}} (x - 1)^{2})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{\frac{1}{11}}, g = (x - 1)^{2}

= \frac{d}{d x} (x^{\frac{1}{11}}) (x - 1)^{2} + \frac{d}{d x} ((x - 1)^{2}) x^{\frac{1}{11}}

\frac{d}{d x} (x^{\frac{1}{11}}) = \frac{1}{11 x ^{\frac{10}{11}}}

\frac{d}{d x} ((x - 1)^{2}) = 2 (x - 1)

= \frac{1}{11 x ^{\frac{10}{11}}} (x - 1)^{2} + 2 (x - 1) x^{\frac{1}{11}}

Simplify

\frac{1}{11 x ^{\frac{10}{11}}} (x - 1)^{2} + 2 (x - 1) x^{\frac{1}{11}} : \frac{23 x ^{2} - 24 x + 1}{11 x ^{\frac{10}{11}}}

= \frac{23 x ^{2} - 24 x + 1}{11 x ^{\frac{10}{11}}}

x \to \infty lim (6^{-})

y = lo g_{10} (e^{x})

\int \frac{1}{( x + 2 ) ( x + 5 )} d x

\frac{\partial}{\partial x} (\frac{x}{y} + sin (2 x + 3 y))

\int_{0}^{6} \frac{1}{u ^{2} - 36} d u

What is the derivative of x^{1/11}(x-1^2) ?
The derivative of x^{1/11}(x-1^2) is (23x^2-24x+1)/(11x^{10/11)}
What is the first derivative of x^{1/11}(x-1^2) ?
The first derivative of x^{1/11}(x-1^2) is (23x^2-24x+1)/(11x^{10/11)}