What is the integral of (tan^2(sqrt(x)))/(sqrt(x)) ?

The integral of (tan^2(sqrt(x)))/(sqrt(x)) is -2sqrt(x)+2tan(sqrt(x))+C

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integral of (tan^2(sqrt(x)))/(sqrt(x))

\int \frac{tan ^{2} ( x )}{x} d x

- 2 x + 2 tan (x) + C

Solution steps

\int \frac{tan ^{2} ( x )}{x} d x

Rewrite using trig identities

= \int \frac{- 1 + sec ^{2} ( x )}{x} d x

Expand

\frac{- 1 + sec ^{2} ( x )}{x} : - \frac{1}{x} + \frac{sec ^{2} ( x )}{x}

= \int - \frac{1}{x} + \frac{sec ^{2} ( x )}{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int \frac{1}{x} d x + \int \frac{sec ^{2} ( x )}{x} d x

\int \frac{1}{x} d x = 2 x

\int \frac{sec ^{2} ( x )}{x} d x = 2 tan (x)

= - 2 x + 2 tan (x)

Add a constant to the solution

= - 2 x + 2 tan (x) + C

\frac{d}{d x} (\frac{3 cos ( x )}{x ^{4} - 2 x + 2})

f (θ) = sec (θ)

- 0.02 x^{3} + 0.37 x^{2} + 241 x + 17905

(\frac{t}{t + 1 ( t )})^{^{'}}

y^{^{'}} + \frac{y}{x} = \frac{1}{x ^{2}}

What is the integral of (tan^2(sqrt(x)))/(sqrt(x)) ?
The integral of (tan^2(sqrt(x)))/(sqrt(x)) is -2sqrt(x)+2tan(sqrt(x))+C