What is the tangent of y=4sin(pix+y),(1,0) ?

The tangent of y=4sin(pix+y),(1,0) is y=-(4pi)/5 x+(4pi)/5

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tangent of y=4sin(pix+y),(1,0)

tangent of

y = 4 sin (π x + y), (1, 0)

y = - \frac{4 π}{5} x + \frac{4 π}{5}

Solution steps

Find the slope of

y = 4 sin (π x + y) : \frac{d y}{d x} = \frac{4 π cos ( π x + y )}{1 - 4 cos ( y + π x )}

Compute the slope of

y = 4 sin (π x + y)

(1, 0) : m = - \frac{4 π}{5}

Find the line with slope m=

- \frac{4 π}{5}

and passing through

(1, 0) : y = - \frac{4 π}{5} x + \frac{4 π}{5}

y = - \frac{4 π}{5} x + \frac{4 π}{5}

n = 0 \sum \infty 6 (- \frac{2}{3})^{n}

y^{^{'}} = \frac{y ^{4} - 3}{( 4 x y ^{3} )}

x \to - 1 lim (4 x^{2} - 3 x + 2)

\int \frac{1}{x ^{4} x ^{2} - 1} d x

\frac{\partial}{\partial x} (e^{x} sin (x + y))

What is the tangent of y=4sin(pix+y),(1,0) ?
The tangent of y=4sin(pix+y),(1,0) is y=-(4pi)/5 x+(4pi)/5