What is the derivative of f(x)=e^xsin(x)-3e^xcos(x) ?

The derivative of f(x)=e^xsin(x)-3e^xcos(x) is 4e^xsin(x)-2e^xcos(x)

What is the first derivative of f(x)=e^xsin(x)-3e^xcos(x) ?

The first derivative of f(x)=e^xsin(x)-3e^xcos(x) is 4e^xsin(x)-2e^xcos(x)

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derivative of

f (x) = e^{x} sin (x) - 3 e^{x} cos (x)

4 e^{x} sin (x) - 2 e^{x} cos (x)

Solution steps

\frac{d}{d x} (e^{x} sin (x) - 3 e^{x} cos (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{x} sin (x)) - \frac{d}{d x} (3 e^{x} cos (x))

\frac{d}{d x} (e^{x} sin (x)) = e^{x} sin (x) + cos (x) e^{x}

\frac{d}{d x} (3 e^{x} cos (x)) = 3 (e^{x} cos (x) - e^{x} sin (x))

= e^{x} sin (x) + cos (x) e^{x} - 3 (e^{x} cos (x) - e^{x} sin (x))

Simplify

e^{x} sin (x) + cos (x) e^{x} - 3 (e^{x} cos (x) - e^{x} sin (x)) : 4 e^{x} sin (x) - 2 e^{x} cos (x)

= 4 e^{x} sin (x) - 2 e^{x} cos (x)

\frac{d}{d x} (\frac{x ^{3} - a x}{b x})

f (t) = sin^{3} (t)

y^{^{''}} - y^{^{'}} - 2 y = 0

f (t) = 7 sin (4 (t + 2)) + 3 cos (4 t - 2)

\int \frac{2 x}{x ^{2} + 3} d x

What is the derivative of f(x)=e^xsin(x)-3e^xcos(x) ?
The derivative of f(x)=e^xsin(x)-3e^xcos(x) is 4e^xsin(x)-2e^xcos(x)
What is the first derivative of f(x)=e^xsin(x)-3e^xcos(x) ?
The first derivative of f(x)=e^xsin(x)-3e^xcos(x) is 4e^xsin(x)-2e^xcos(x)