What is the integral of 1/(x\sqrt[5]{x)} ?

The integral of 1/(x\sqrt[5]{x)} is -5/(\sqrt[5]{x)}+C

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integral of 1/(x\sqrt[5]{x)}

Solution steps

Simplify

= \int \frac{1}{x ^{\frac{6}{5}}} d x

Apply the Power Rule

Add a constant to the solution

(x + y) d x + (3 x + 3 y - 4) d y = 0

\frac{d}{d x} (e^{- 4 x^{3} - 2 x + 4})

f (x) = 6 (ln (x + 1))

e^{x} - x^{7}

x \to 0 - lim (9 + \frac{2}{x})

What is the integral of 1/(x\sqrt[5]{x)} ?
The integral of 1/(x\sqrt[5]{x)} is -5/(\sqrt[5]{x)}+C