What is the tangent of 3x^2-1,\at x=-2 ?

The tangent of 3x^2-1,\at x=-2 is y=-12x-13

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tangent of 3x^2-1,\at x=-2

tangent of

3 x^{2} - 1, at x = - 2

y = - 12 x - 13

Solution steps

Find the tangent point:

(- 2, 11)

Find the slope of

y = 3 x^{2} - 1 : \frac{d y}{d x} = 6 x

Compute the slope of

y = 3 x^{2} - 1

x = - 2 : m = - 12

Find the line with slope m=

- 12

and passing through

(- 2, 11) : y = - 12 x - 13

y = - 12 x - 13

y = \frac{x ^{2} + 2}{x + 8}, (3, 1)

\int 2 e^{3 x - 5} d x

x \to π lim (tan (\frac{5 x}{3}))

\int - 2 + 36 x - 12 x^{2} d x

x \to 81 lim (x^{\frac{3}{2}})

What is the tangent of 3x^2-1,\at x=-2 ?
The tangent of 3x^2-1,\at x=-2 is y=-12x-13