What is the integral from 1 to infinity of x^2 ?

The integral from 1 to infinity of x^2 is diverges

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integral from 1 to infinity of x^2

\int_{1}^{\infty} x^{2} d x

diverges

Solution steps

\int_{1}^{\infty} x^{2} d x

Compute the indefinite integral:

\int x^{2} d x = \frac{x ^{3}}{3} + C

Compute the boundaries:

\int_{1}^{\infty} x^{2} d x =

diverges

= diverges

f (x) = \frac{2 x ^{2} + 6 x + 6}{x + 1}

\frac{d y}{d x} = e^{4 y} sin (5 x)

\frac{\partial}{\partial x} (6 x + 4 y)

\int (x^{4})^{\frac{1}{2}} d x

h \to \frac{π}{2} lim (\frac{( 1 - cos ( 3 h ) )}{h})

What is the integral from 1 to infinity of x^2 ?
The integral from 1 to infinity of x^2 is diverges