What is area 4t^3-t^2,t^4+2t^2,1<= t<= 3 ?

The answer to area 4t^3-t^2,t^4+2t^2,1<= t<= 3 is 28/5

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area 4t^3-t^2,t^4+2t^2,1<= t<= 3

area

4 t^{3} - t^{2}, t^{4} + 2 t^{2}, 1 \leq t \leq 3

\frac{28}{5}

Decimal Notation

5.6

Solution steps

Apply the area formula:

\int_{1}^{3} 4 t^{3} - t^{2} - (t^{4} + 2 t^{2}) d t

Solve

\int_{1}^{3} 4 t^{3} - t^{2} - (t^{4} + 2 t^{2}) d t : \frac{28}{5}

The area is:

= \frac{28}{5}

\int_{0}^{\infty} t e^{- 3 t} d t

x \to 6 lim (8 (x - 5) (x - 7))

\frac{\partial}{\partial x} (5 x y \cdot e^{- x^{2} y})

y = 4 x - x^{2}

\int \frac{8 x ^{3}}{3 y ^{2}}

What is area 4t^3-t^2,t^4+2t^2,1<= t<= 3 ?
The answer to area 4t^3-t^2,t^4+2t^2,1<= t<= 3 is 28/5