What is the solution for y^{''}+6y^'+13=0 ?

The solution for y^{''}+6y^'+13=0 is y=c_{1}+c_{2}e^{-6t}-(13t)/6

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y^{''}+6y^'+13=0

y^{^{''}} + 6 y^{^{'}} + 13 = 0

y = c_{1} + c_{2} e^{- 6 t} - \frac{13 t}{6}

Solution steps

y^{''} (t) + 6 y^{'} (t) + 13 = 0

Solve linear ODE:

y = c_{1} + c_{2} e^{- 6 t} - \frac{13 t}{6}

y = c_{1} + c_{2} e^{- 6 t} - \frac{13 t}{6}

\int \frac{1}{16} e^{4 x} d x

\frac{d}{d x} (\frac{x ^{2}}{sin ( a x )})

\frac{x ^{2}}{( 5 + x ) ^{4}}

x \to - 7 lim (f (x))

\frac{2.98}{9 + s ^{2}}

What is the solution for y^{''}+6y^'+13=0 ?
The solution for y^{''}+6y^'+13=0 is y=c_{1}+c_{2}e^{-6t}-(13t)/6