What is the solution for y^{''}+9y=5cos(2x) ?

The solution for y^{''}+9y=5cos(2x) is y=c_{1}cos(3x)+c_{2}sin(3x)+cos(2x)

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y^{''}+9y=5cos(2x)

y^{^{''}} + 9 y = 5 cos (2 x)

y = c_{1} cos (3 x) + c_{2} sin (3 x) + cos (2 x)

Solution steps

y^{''} (x) + 9 y = 5 cos (2 x)

Solve linear ODE:

y = c_{1} cos (3 x) + c_{2} sin (3 x) + cos (2 x)

y = c_{1} cos (3 x) + c_{2} sin (3 x) + cos (2 x)

f (x) = e^{s i n (x)}

x \to \infty lim ([8, x])

\frac{- 75 s - 25}{1 - 3 s ^{2}}

\int_{0}^{2} \frac{x}{( 3 - x ) ^{2}} d x

\frac{4 s}{s ^{2} + 4}

What is the solution for y^{''}+9y=5cos(2x) ?
The solution for y^{''}+9y=5cos(2x) is y=c_{1}cos(3x)+c_{2}sin(3x)+cos(2x)