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Popular >

derivative of 20t-1/2 {g}(t,xt^2)

Solution

\frac{d}{d x} (20 t - \frac{1}{2} g (t, x) t^{2})

Solution

0 - \frac{1}{2} t^{2} \frac{d}{d x} (g (t, x))

Solution steps

\frac{d}{d x} (20 t - \frac{1}{2} g (t, x) t^{2})

Treat

t

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (20 t) - \frac{d}{d x} (\frac{1}{2} g (t, x) t^{2})

\frac{d}{d x} (20 t) = 0

\frac{d}{d x} (\frac{1}{2} g (t, x) t^{2}) = \frac{1}{2} t^{2} \frac{d}{d x} (g (t, x))

= 0 - \frac{1}{2} t^{2} \frac{d}{d x} (g (t, x))

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Frequently Asked Questions (FAQ)

What is the derivative of 20t-1/2 {g}(t,xt^2) ?
The derivative of 20t-1/2 {g}(t,xt^2) is 0-1/2 t^2 derivative of {g}(t,x)
What is the first derivative of 20t-1/2 {g}(t,xt^2) ?
The first derivative of 20t-1/2 {g}(t,xt^2) is 0-1/2 t^2 derivative of {g}(t,x)