What is the derivative of 1/(2x)+2x ?

The derivative of 1/(2x)+2x is -1/(2x^2)+2

What is the first derivative of 1/(2x)+2x ?

The first derivative of 1/(2x)+2x is -1/(2x^2)+2

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derivative of

\frac{1}{2 x} + 2 x

- \frac{1}{2 x ^{2}} + 2

Solution steps

\frac{d}{d x} (\frac{1}{2 x} + 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{1}{2 x}) + \frac{d}{d x} (2 x)

\frac{d}{d x} (\frac{1}{2 x}) = - \frac{1}{2 x ^{2}}

\frac{d}{d x} (2 x) = 2

= - \frac{1}{2 x ^{2}} + 2

f (x) = (x + 2)^{x^{2} - 2 x + 1}

\int_{3}^{5} \frac{x}{x ^{2} - 2} d x

\int \frac{2 x + 2}{x ^{2} + 2 x - 1} d x

\int 4 x^{2} sin (π x) d x

What is the derivative of 1/(2x)+2x ?
The derivative of 1/(2x)+2x is -1/(2x^2)+2
What is the first derivative of 1/(2x)+2x ?
The first derivative of 1/(2x)+2x is -1/(2x^2)+2